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407244748 查看數據表(PDF) - Tyco Electronics

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407244748 Datasheet PDF : 20 Pages
First Prev 11 12 13 14 15 16 17 18 19 20
Data Sheet
July 1999
JW050A, JW075A, JW100A, JW150A Power Modules:
dc-dc Converters; 36 to 75 Vdc Input, 5 Vdc Output; 50 W to 150 W
Thermal Considerations (continued)
Heat Transfer with Heat Sinks
The power modules have through-threaded, M3 x 0.5
mounting holes, which enable heat sinks or cold plates
to attach to the module. The mounting torque must not
exceed 0.56 N-m (5 in.-lb.). For a screw attachment
from the pin side, the recommended hole size on the
customer’s PWB around the mounting holes is
0.130 ± 0.005 inches. If a larger hole is used, the
mounting torque from the pin side must not exceed
0.25 N-m (2.2 in.-lb.).
Thermal derating with heat sinks is expressed by using
the overall thermal resistance of the module. Total mod-
ule thermal resistance (θca) is defined as the maximum
case temperature rise (TC, max) divided by the module
power dissipation (PD):
θca =
TC, max
-------P-----D--------
=
(TC TA)
---------P-----D----------
The location to measure case temperature (TC) is
shown in Figure 26. Case-to-ambient thermal resis-
tance vs. airflow is shown, for various heat sink config-
urations and heights, in Figure 32. These curves were
obtained by experimental testing of heat sinks, which
are offered in the product catalog.
8
7
1 1/2 IN. HEAT SINK
1 IN. HEAT SINK
6
1/2 IN. HEAT SINK
1/4 IN. HEAT SINK
5
NO HEAT SINK
4
3
2
1
0
0
0.5
1.0
1.5
2.0
2.5 3.0
(100) (200) (300) (400) (500) (600)
AIR VELOCITY, m/s (ft./min.)
8-1153 (C)
Figure 32. Case-to-Ambient Thermal Resistance
Curves; Either Orientation
These measured resistances are from heat transfer
from the sides and bottom of the module as well as the
top side with the attached heat sink; therefore, the
case-to-ambient thermal resistances shown are gener-
ally lower than the resistance of the heat sink by itself.
The module used to collect the data in Figure 32 had a
thermal-conductive dry pad between the case and the
heat sink to minimize contact resistance. The use of
Figure 32 is shown in the following example.
Example
If an 85 °C case temperature is desired, what is the
minimum airflow necessary? Assume the JW100A
module is operating at VI = 54 V and an output current
of 20 A, maximum ambient air temperature of 40 °C,
and the heat sink is 1/2 inch.
Solution
Given: VI = 54 V
IO = 20 A
TA = 40 °C
TC = 85 °C
Heat sink = 1/2 in.
Determine PD by using Figure 30:
PD = 17 W
Then solve the following equation:
θca =
(TC TA)
---------P-----D----------
θca =
(85 40)
---------1----7----------
θca = 2.6 °C/W
Use Figure 32 to determine air velocity for the 1/2 inch
heat sink.
The minimum airflow necessary for the JW100A mod-
ule is 1.3 m/s (260 ft./min.).
Tyco Electronics Corp
15

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