Open-load detection
ON-state diagnostic condition: VON < RON * IL(OL); IN
high
+ Vbb
ON
Logic
unit
Open load
detection
VON
OUT
GND disconnect
IN
2
ST
4
Vbb VIN VST
3
Vbb
PROFET
OUT
5
GND
1 VGND
Any kind of load. In case of Input=high is VOUT ≈ VIN - VIN(T+) .
Due to VGND >0, no VST = low signal available.
GND disconnect with GND pull up
IN
2
ST
4
3
Vbb
PROFET
GND
1
OUT
5
Vbb
VIN VST
VGND
Any kind of load. If VGND > VIN - VIN(T+) device stays off
Due to VGND >0, no VST = low signal available.
BTS 410 F2
Vbb disconnect with energized inductive
load
3
high
IN
Vbb
2
ST
4
PROFET
GND
OUT
5
1
Vbb
Normal load current can be handled by the PROFET
itself.
Vbb disconnect with charged external
inductive load
S
3
high
IN
Vbb
2
PROFET
OUT
5
D
ST
4
GND
1
Vbb
If other external inductive loads L are connected to the PROFET,
additional elements like D are necessary.
Inductive Load switch-off energy
dissipation
E bb
E AS
IN
Vbb
ELoad
PROFET OUT
=
ST
EL
GND
L
{Z L RL
ER
Energy stored in load inductance:
EL = 1/2·L·I2L
While demagnetizing load inductance, the energy
dissipated in PROFET is
∫ EAS= Ebb + EL - ER= VON(CL)·iL(t) dt,
Semiconductor Group
7