LT8302
Applications Information
Design Example
Use the following design example as a guide to designing
applications for the LT8302. The design example involves
designing a 5V output with a 1.5A load current and an
input range from 8V to 32V.
VIN(MIN) = 8V, VIN(NOM) = 12V, VIN(MAX) = 32V,
VOUT = 5V, IOUT = 1.5A
Step 1: Select the transformer turns ratio.
NPS
<
65V
–
VIN(MAX) – VLEAKAGE
VOUT + VF
VLEAKAGE = Margin for transformer leakage spike = 15V
VF = Output diode forward voltage = ~0.3V
Example:
NPS
<
65V – 32V – 15V
5V + 0.3V
=
3.4
The choice of transformer turns ratio is critical in determin-
ing output current capability of the converter. Table 2 shows
the switch voltage stress and output current capability at
different transformer turns ratio.
Table 2. Switch Voltage Stress and Output Current Capability vs
Turns Ratio
VSW(MAX) at
NPS
VIN(MAX) (V)
1:1
37.3
IOUT(MAX) at
VIN(MIN) (A)
0.92
DUTY CYCLE (%)
14-40
2:1
42.6
1.31
25-57
3:1
47.9
1.53
33-67
Clearly, only NPS = 3 can meet the 1.5A output current
requirement, so NPS = 3 is chosen as the turns ratio in
this example.
Step 2: Determine the primary inductance.
Primary inductance for the transformer must be set above
a minimum value to satisfy the minimum switch-off and
switch-on time requirements:
( ) LPRI
≥
tOFF(MIN)
• NPS • VOUT
ISW(MIN)
+
VF
LPRI
≥
tON(MIN) • VIN(MAX)
ISW(MIN)
tOFF(MIN) = 350ns
tON(MIN) = 160ns
ISW(MIN) = 0.87A
Example:
LPRI
≥
350ns
•
3 • (5V
0.87A
+
0.3V
)
=
6.4µH
LPRI
≥
160ns • 32V
0.87A
=
5.9µH
Most transformers specify primary inductance with a toler-
ance of ±20%. With other component tolerance considered,
choose a transformer with its primary inductance 40% to
60% larger than the minimum values calculated above.
LPRI = 9µH is then chosen in this example.
Once the primary inductance has been determined, the
maximum load switching frequency can be calculated as:
( ) fSW
=
tON
1
+ tOFF
=
LPRI • ISW
VIN
1
+
LPRI • ISW
NPS • VOUT +
VF
ISW
=
VOUT
η•
• IOUT •
VIN • D
2
8302fa
18
For more information www.linear.com/LT8302